Representation Theory
The Adjoint Representation: A Lie Algebra Acting on Itself
Every Lie algebra carries a canonical representation on itself — no auxiliary vector space required — and this single construction encodes the group's curvature, its Killing form, its root decomposition, and the entire classification of simple Lie algebras. The adjoint representation ad: 𝔤 → 𝔤𝔩(𝔤) sends each element X to the linear map ad_X(Y) = [X, Y], turning the bracket into a homomorphism whose Jacobi identity is nothing but the statement that ad is a Lie algebra representation.
At the group level, Ad: G → GL(𝔤) is conjugation acting on the tangent space at the identity, Ad_g = d(c_g)_e where c_g(h) = g h g⁻¹, and its differential at the identity recovers ad. This is the bridge on which the exponential map, the Baker–Campbell–Hausdorff formula, and the structure theory of semisimple groups all rest.
- FieldLie theory / representation theory
- Definitionad_X(Y) = [X, Y], a map 𝔤 → 𝔤𝔩(𝔤)
- Group versionAd_g = d(c_g)_e, conjugation on 𝔤 = T_e G
- Key identityJacobi ⟺ ad is a Lie algebra homomorphism
- Named afterSophus Lie (1870s); Killing, Cartan (1888–1894)
- Kernelker(ad) = center 𝔷(𝔤); ker(Ad) = Z(G)
Watch the 60-second explainer
A condensed visual walkthrough — narrated, captioned, under a minute.
Precise statement: two maps and one differential
Let 𝔤 be a Lie algebra over a field k with bracket [·,·]. The adjoint representation is the linear map ad: 𝔤 → 𝔤𝔩(𝔤) = End(𝔤), X ↦ ad_X, where ad_X(Y) = [X, Y]. The claim is that ad is a homomorphism of Lie algebras: ad_[X,Y] = [ad_X, ad_Y] = ad_X ad_Y − ad_Y ad_X, where the bracket on the right is the commutator of endomorphisms.
For a Lie group G with Lie algebra 𝔤 ≅ T_e G, define c_g(h) = g h g⁻¹ (inner automorphism) and set Ad_g = d(c_g)_e ∈ GL(𝔤). Then Ad: G → GL(𝔤) is a smooth group homomorphism (a representation on 𝔤), and its differential at the identity is exactly ad: d(Ad)_e = ad. Equivalently, for all X ∈ 𝔤 one has the fundamental relation Ad(exp X) = exp(ad_X), an equality of operators on 𝔤. For a matrix Lie group these specialize to Ad_g(Y) = gYg⁻¹ and ad_X(Y) = XY − YX.
The picture: conjugation seen from the tangent space
The intuition is conjugation, linearized. The map c_g measures how far G is from abelian: if G were commutative, c_g would be the identity for every g. Ad_g captures the infinitesimal distortion conjugation induces on tangent vectors at e. So Ad packages the entire family of inner automorphisms into a single linear action on the fixed vector space 𝔤.
Differentiating once more in g gives ad. Concretely, ad_X is the infinitesimal generator of the flow Y ↦ Ad(exp(tX))Y, so d/dt|₀ Ad(exp tX)Y = [X, Y]. Thus ad_X is the Lie derivative of the vector field along the one-parameter subgroup exp(tX): the bracket [X,Y] is exactly the failure of the flows of X and Y to commute, to first order. The adjoint representation is therefore the algebraic shadow of curvature — it is how the group 'twists' its own tangent directions into one another.
Key idea: the Jacobi identity IS a representation
The proof that ad is a homomorphism is the Jacobi identity in disguise, and this is the mechanism worth internalizing. We must show ad_[X,Y] = ad_X ad_Y − ad_Y ad_X. Apply both sides to an arbitrary Z:
Left side: ad_[X,Y](Z) = [[X,Y], Z].
Right side: ad_X ad_Y(Z) − ad_Y ad_X(Z) = [X,[Y,Z]] − [Y,[X,Z]].
These agree precisely when [[X,Y],Z] = [X,[Y,Z]] − [Y,[X,Z]], which, rearranged using antisymmetry, is the Jacobi identity [X,[Y,Z]] + [Y,[Z,X]] + [Z,[X,Y]] = 0. So ad being a representation is logically equivalent to Jacobi — no computation beyond bookkeeping is needed.
For the group side, Ad_g Ad_h = d(c_g)_e d(c_h)_e = d(c_g ∘ c_h)_e = d(c_{gh})_e = Ad_{gh} by the chain rule and c_g ∘ c_h = c_{gh}. Differentiating the identity Ad(exp X) = exp(ad_X) at X = 0 in the direction X recovers d(Ad)_e = ad.
Worked example: 𝔰𝔲(2) and 𝔰𝔬(3)
Take 𝔤 = 𝔰𝔲(2) with basis X₁, X₂, X₃ satisfying [Xᵢ, Xⱼ] = ε_{ijk} Xₖ (the structure constants are the Levi-Civita symbol). Compute ad_{X₁} in this basis: ad_{X₁}(X₂) = [X₁,X₂] = X₃ and ad_{X₁}(X₃) = [X₁,X₃] = −X₂, while ad_{X₁}(X₁)=0. So the matrix of ad_{X₁} is the 3×3 generator of rotations about the first axis — the adjoint representation of 𝔰𝔲(2) is 𝔰𝔬(3) acting on ℝ³.
Exponentiating, Ad(exp(θX₁)) = exp(θ ad_{X₁}) is rotation by θ about the X₁-axis. This is the concrete face of the famous 2-to-1 cover SU(2) → SO(3): the group Ad(SU(2)) = SO(3), and the kernel of Ad is the center {±I}. The adjoint map literally exhibits SO(3) as SU(2) modulo its center, and shows why a 720° rotation in SU(2) descends to a 360° rotation in SO(3).
Where hypotheses bite: center, semisimplicity, and the Killing form
Faithfulness of ad requires a trivial center: ker(ad) = 𝔷(𝔤) = {X : [X,Y]=0 ∀Y}. For abelian 𝔤 (e.g. ℝⁿ with zero bracket) ad ≡ 0, so the adjoint representation is useless — it forgets everything. Thus 'a Lie algebra acting on itself' is informative exactly to the extent that 𝔤 is non-abelian. At the group level ker(Ad) = Z(G), the full center, for connected G (the differential statement ker(ad) = 𝔷(𝔤) = Lie(Z(G)) only sees the identity component Z(G)°, but Ad itself kills the whole center, including its finite part), so Ad detects G only up to its center.
The payoff appears under semisimplicity. Cartan's criterion: 𝔤 is semisimple iff the Killing form κ(X,Y) = tr(ad_X ad_Y) is non-degenerate. Here the invariance κ(ad_Z X, Y) + κ(X, ad_Z Y) = 0 (ad-invariance) is what makes κ a genuine tool. Drop semisimplicity and κ degenerates — its radical is a solvable ideal — and root-space theory collapses. Connections: the whole Cartan–Killing classification, compactness (κ negative-definite ⟺ compact semisimple), and Whitehead's lemmas / Lie algebra cohomology all hinge on this form built from ad.
Why it matters: roots, curvature, and BCH
The adjoint representation is the engine of semisimple structure theory. Fix a Cartan subalgebra 𝔥 ⊂ 𝔤; the operators {ad_H : H ∈ 𝔥} commute and are simultaneously diagonalizable, giving the root space decomposition 𝔤 = 𝔥 ⊕ ⨁_{α∈Φ} 𝔤_α, where 𝔤_α = {X : ad_H X = α(H)X ∀H}. The roots α are eigenvalues of the adjoint action; the entire A–D–E classification of simple Lie algebras is read off from how these root vectors bracket, i.e. from ad restricted to root spaces.
Beyond classification, Ad(exp X) = exp(ad_X) is the algebraic core of the Baker–Campbell–Hausdorff formula exp X exp Y = exp(X + Y + ½[X,Y] + …), whose higher terms are iterated ad's. In differential geometry, ad governs the curvature of bi-invariant metrics (R(X,Y)Z = −¼[[X,Y],Z]) and the holonomy of principal bundles. In physics it is the gauge field's transformation law: the field strength lives in the adjoint. It is, in short, the representation you cannot avoid.
| Feature | ad: 𝔤 → 𝔤𝔩(𝔤) | Ad: G → GL(𝔤) |
|---|---|---|
| Formula | ad_X(Y) = [X, Y] | Ad_g(Y) = d(c_g)_e(Y), c_g(h)=ghg⁻¹ |
| For matrix groups | ad_X(Y) = XY − YX | Ad_g(Y) = g Y g⁻¹ |
| Kernel | center 𝔷(𝔤) = {X : [X,·]=0} | Z(G) for connected G; the full center |
| Linking identity | d(Ad)_e = ad | Ad(exp X) = exp(ad_X) |
| Invariant form | Killing κ(X,Y)=tr(ad_X ad_Y) | κ(Ad_g X, Ad_g Y) = κ(X,Y) |
| Faithful when | 𝔤 has trivial center | G connected, semisimple, centerless |
Frequently asked questions
Why is ad automatically a Lie algebra homomorphism?
Because the requirement ad_[X,Y] = [ad_X, ad_Y] is exactly the Jacobi identity. Applying both sides to a vector Z and expanding via the bracket, the equation [[X,Y],Z] = [X,[Y,Z]] − [Y,[X,Z]] is Jacobi rearranged using antisymmetry. So no extra hypothesis is needed: any Lie algebra satisfies Jacobi by definition, hence ad is always a representation.
When is the adjoint representation faithful?
ad is faithful iff its kernel, the center 𝔷(𝔤) = {X : [X,Y]=0 for all Y}, is zero. Semisimple Lie algebras have trivial center, so for them ad is faithful and embeds 𝔤 ↪ 𝔤𝔩(𝔤) — this is one proof that every semisimple Lie algebra is linear. For abelian 𝔤, ad ≡ 0, the opposite extreme.
How exactly do ad and Ad relate?
Ad is the group representation g ↦ d(c_g)_e coming from conjugation, and ad is its differential at the identity: d(Ad)_e = ad. The two are tied by Ad(exp X) = exp(ad_X), an equality of operators on 𝔤. Differentiating Ad(exp tX) at t = 0 gives ad_X, and this is how the group-level twisting linearizes to the bracket [X,·].
What is the Killing form and why build it from ad?
κ(X,Y) = tr(ad_X ad_Y) is a symmetric bilinear form intrinsic to 𝔤, requiring no chosen representation — only the bracket. It is ad-invariant: κ([Z,X],Y) + κ(X,[Z,Y]) = 0. Cartan's criterion says 𝔤 is semisimple iff κ is non-degenerate, and κ is negative-definite iff 𝔤 is the Lie algebra of a compact semisimple group. So κ diagnoses the deepest structural facts using only ad.
Does the adjoint representation see the whole group?
No — Ad only detects G up to its center. For connected G, ker(Ad) = Z(G) (the full center), so Ad(G) ≅ G/Z(G), the adjoint group. The example SU(2) → SO(3) has kernel {±I}: the adjoint representation collapses the two-element center, which is why SO(3) is the 'centerless' or adjoint form of the SU(2)-type group.
How does ad produce the roots of a semisimple Lie algebra?
Pick a Cartan subalgebra 𝔥 (a maximal abelian subalgebra of semisimple elements). The commuting operators ad_H, H ∈ 𝔥, are simultaneously diagonalizable, decomposing 𝔤 into eigenspaces 𝔤_α where ad_H acts by the scalar α(H). The nonzero eigenfunctionals α ∈ 𝔥* are the roots, and the combinatorics of how root vectors bracket under ad is precisely the root system that classifies 𝔤.